integrate 2e^(2x)
⚠ 2e is read as the product 2*e: for a power, write 2^e‖2x is read as the product 2*x: for a power, write 2^x
Let's integrate: ∫(2e(2x))dx
For the math expression: 2e(2x), we know the derivative formula: ddx(exp(a)) = exp(a), so we try differentiating with exp
Let's perform the differentiation: ddx(exp(2x))
We differentiate using: ddx(exp(f)) = ddx(f)·exp(f) (where f = 2x)
ddx(2x)·exp(2x)
2exp(2x)
The computed derivative matches the original math expression up to a constant factor. Therefore, the integral is:
22·e(2x)
ℹ22 = 1‖1·e(2x) = e(2x)
e(2x)
▶Indefinite integrals are defined up to an additive constant C, so this yields: e(2x) + C