integrate 2e^(2x)
Let's integrate: ∫(2e(2x))dx
We attempt to reverse an integration: starting from 2e(2x) and (exp(a))' = exp(a), we differentiate using exp
Let's differentiate: (exp(2x))'
We differentiate using: (exp(f))' = (f)'·exp(f) (where f = 2x)
(2x)'·exp(2x)
2exp(2x)
The computed derivative matches the original math expression up to a constant factor. Therefore, the integral is:
22·e(2x)
e(2x)
Indefinite integrals are defined up to an additive constant C, so this yields: e(2x) + C
Result:   e(2x) + C, with C being any constant