integrate 2x+3
Let's compute the integral: ∫(2x + 3)dx
∫(2x)dx + ∫(3)dx
∫(2*x)dx = 2·x22∫(3)dx = 3x
2·x22 + 3x
2·x22 = 2x222x22 = x2
x2 + 3x
You can write the expression in factored form: x·(x + 3)
Indefinite integrals are defined up to an additive constant C, so this yields: x·(x + 3) + C
Answer:   x·(x + 3) + C, with C being any constant