Let's compute the integral: ∫(2x + 3)dx ∫(2x)dx + ∫(3)dx ℹ∫(2*x)dx = 2·x22‖∫(3)dx = 3x 2·x22 + 3x ℹ2·x22 = 2x22‖2x22 = x2 x2 + 3x You can write the expression in factored form: x·(x + 3) Indefinite integrals are defined up to an additive constant C, so this yields: x·(x + 3) + C ▷Answer: x·(x + 3) + C, with C being any constant