Let's integrate: ∫(x)dx Use the integration formula for x: ∫(xn)dx = x(n + 1)n + 1 x(12 + 1)12 + 1 ℹ12 + 1 = 1 + 22‖12 + 1 = 1 + 22 x(1 + 22)1 + 22 ℹ1 + 2 = 3‖1 + 2 = 3 x3232 x32·23 Indefinite integrals are defined up to an additive constant C, so this yields: 2x323 + C ▷Result: 2x323 + C, with C being any constant