Let's compute the integral: ∫(x + 1)dx ∫(x)dx + ∫(1)dx ℹ∫(x)dx = x22‖∫(1)dx = x x22 + x Indefinite integrals are defined up to an additive constant C, so this yields: x22 + x + C ▷Answer: x22 + x + C, where C is a constant