integrate x+1
Let's compute the integral: ∫(x + 1)dx
∫(x)dx + ∫(1)dx
∫(x)dx = x22∫(1)dx = x
x22 + x
Indefinite integrals are defined up to an additive constant C, so this yields: x22 + x + C
Answer:   x22 + x + C, where C is a constant