Let's integrate: ∫(x2 + 1)dx ∫(x2)dx + ∫(1)dx ℹ∫(x^2)dx = x33‖∫(1)dx = x x33 + x Indefinite integrals are defined up to an additive constant C, so this yields: x33 + x + C ▷Result: x33 + x + C, with C being any constant