integrate x^2 between 0 and 2 — step-by-step solution

Let's compute the integral:

\int(x^{2})dx

\frac{x^{3}}{3}

Let's evaluate for the interval

[0, 2]

\frac{2^{3}}{3} - \frac{0^{3}}{3}

ℹ

2^{3}

8

‖

0^{3}

0

‖

\frac{0}{3}

0

\frac{8}{3} + 0

\frac{8}{3}

The approximate value of:

\frac{8}{3}

is:

\approx 2.6667

▷Result: $\frac{8}{3}$

▷▷Numeric value:

\approx 2.6667