intercepts of ln(x)
On the horizontal axis, y = 0: solve ln(x) = 0
⇥Let's solve in ℝ: ln(x) = 0
⇥On the logarithm's domain, ln is strictly increasing: ln(x) = 0 is equivalent to x = 1
⇥Candidates, pending the domain check: x = 1
⇥ For the expression ln(x) to exist, you must check: x > 0
⇥Domain constraints: x > 0
The graph crosses the horizontal axis at (1, 0)
x = 0 is not in the domain: the graph does not cross the vertical axis
▶Axis intercepts:   (1, 0)