inverse laplace 1/(s-2)^2
Find the causal inverse transform, for t ≥ 0. By linearity, invert each partial fraction
The inverse Laplace formula for 1(s -a)n is tn -1·exp(at)(n -1)!; it gives for 1(s -2)2: texp(2t)1!
⇥ⓘ The factorial of a number is the product of all the integers from 1 to that number: 1! = 1
⇥ texp(2t)1
▶Inverse Laplace transform:   texp(2t)