inverse laplace 1/s^2
Find the causal inverse transform, for t ≥ 0. By linearity, invert each partial fraction
The inverse Laplace formula for 1(s -a)n is tn -1·exp(at)(n -1)!; it gives for 1s2: texp(0·t)1!
⇥ⓘ A product with a zero factor is zero: 0·t = 0■Any nonzero number raised to the power 0 is 1: exp(0) = 1■The factorial of a number is the product of all the integers from 1 to that number: 1! = 1
⇥ t1
▶Inverse Laplace transform:   t