limit as x approaches 0 of (x^2)/(1-cos(x))
1) Compute the limit of as
The limit of is ⁺ when
ⓘ The function cos is continuous, its limit is its value at the limit of its argument
The limit of is ⁺ when
⇥1.1) Let's evaluate:
⇥ⓘ The cosine is the x-coordinate (horizontal axis) of the point reached on the unit circle after a rotation of radians from the horizontal axis pointing to the right, this is a remarkable value: =
⇥
ⓘ The limit of a sum of finite limits is the sum of the limits
The limit of is ()⁺ when
⇥1.2) Let's calculate:
⇥ⓘ Start from and move back on the number line, down to zero: =
⇥
For , we encounter the indeterminate form 0/0 as tends to
2) We need a Taylor expansion for:
Using Taylor's formula: for the function cos , we compute the Taylor expansion for X = at the point A = of order N =2
ⓘ The cosine is the x-coordinate (horizontal axis) of the point reached on the unit circle after a rotation of radians from the horizontal axis pointing to the right, this is a remarkable value: = , = ■The sine is the y-coordinate (vertical axis) of the point reached on the unit circle after a rotation of radians from the horizontal axis pointing to the right, this is a remarkable value: = ■Adding 0 changes nothing: = ■Multiplying a fraction by a number multiplies its numerator: = =
ⓘ A product with a zero factor is zero: =
ⓘ Adding 0 changes nothing: =
3) We redo the calculation using the Taylor expansion:
ⓘ The numerator and the denominator are computed before the division: = ■To add fractions, put them over the same denominator, then add the numerators: =
ⓘ A product with a zero factor is zero: =
ⓘ Adding 0 changes nothing: =
ⓘ Dividing is multiplying by the reciprocal: =
ⓘ Multiplying a fraction by a term multiplies its numerator: = ■The original denominator must remain nonzero. The fraction is simplified by dividing the numerator and the denominator by their common factor : =
So the limit of is when
▶Limit: