limit as x approaches 1+ of 5/(x^3-1)
Compute the limit of 5x3 -1 as x → 1⁺
ⓘ The power with a constant exponent is continuous here: substitute the limit of the base
The limit of x3 is 1 when x → 1⁺
ⓘ The limit of a sum of finite limits is the sum of the limits
The limit of x3 -1 is (1 -1)⁺ when x → 1⁺
⇥Let's evaluate: 1 -1
⇥ⓘ Start from 1 and move back 1 on the number line, down to zero: 1 -1 = 0
⇥ 0
ⓘ A nonzero number divided by a quantity that tends to 0 grows without bound, the signs giving +∞ or -∞
So the limit of 5x3 -1 is +∞ when x → 1⁺
▶Limit:   +∞