limit as x approaches 3 of (3-x)/(|x-3|)
⚠ |x-3| is read as the absolute value abs(x-3)
Compute the limit of 3 -xabs(x -3) as x → 3
The limit of 3 -x is 3 -3 when x → 3
⇥Let's calculate: 3 -3
⇥ 0
The limit of x -3 is 3 -3 when x → 3
⇥Let's evaluate: 3 -3
⇥ 0
The limit of abs(x -3) is abs(0) when x → 3
⇥Let's calculate: abs(0)
⇥ 0
For 3 -xabs(x -3), the limit takes the indeterminate form 0/0 when x → 3
On the left, x < 3, so abs(x -3) = -(x -3) and the quotient is 1
On the right, x > 3, so abs(x -3) = x -3 and the quotient is -1
The left and right limits are different: the limit does not exist
So the limit of 3 -xabs(x -3) does not exist when x → 3
▶Limit:   undefined