limit as x approaches 7 of ((1/x-1/7))/(x-7)
1) Compute the limit of 1x -17x -7 as x → 7
The limit of 1x is 17 when x → 7
ⓘ The limit of a sum of finite limits is the sum of the limits
The limit of 1x -17 is 17 -17 when x → 7
⇥1.1) Let's calculate: 17 -17
⇥ⓘ To add fractions, put them over the same denominator, then add the numerators: 17 -17 = 1 -17
⇥ 1 -17
⇥ⓘ The numerator and the denominator are computed before the division: 1 -1 = 0
⇥ 07
⇥ 0
ⓘ The limit of a sum of finite limits is the sum of the limits
The limit of x -7 is 7 -7 when x → 7
⇥1.2) Let's calculate: 7 -7
⇥ⓘ Start from 7 and move back 7 on the number line, down to zero: 7 -7 = 0
⇥ 0
For 1x -17x -7, the limit takes the indeterminate form 0/0 when x → 7
2) To find the limit, we factorize the numerator and the denominator:
3) Let's add fractions: 1x -17
ⓘ To add fractions, put them over the same denominator, then add the numerators: 1x -17 = 7 -1·xx·7
7 -1·xx·7
ⓘ Multiplying by 1 changes nothing: 1·x = x
7 -xx·7
We factorize the numerator and the denominator by looking for their roots; those of the denominator will be forbidden values
The roots of the denominator are the forbidden values: x ≠ 0
Factors found: 7 -x7x
4) Let's simplify: 7 -x7xx -7
ⓘ Dividing a fraction by x -7 is multiplying its denominator by x -7: 7 -x7xx -7 = 7 -x7x·(x -7)
7 -x7x·(x -7)
We simplify the fraction: 7 -xx -7 by the common factor: -7 + x to get the new expression: -1
-17x
ⓘ The limit of a product of finite limits is the product of the limits
The limit of 7x is 7·7 when x → 7
Let's calculate: 7·7
ⅰ 7·7 = 49
49
The limit of -17x is -149 when x → 7
So the limit of 1x -17x -7 is -149 when x → 7
▶Limit:   -149
5) The numeric value of: -149 is:
▷ ≈ -2.0408×10-2