limit as x approaches -1 of 3x^4-6x+1
1) Compute the limit of 3x4 -6x + 1 as x → -1
ⓘ The power with a constant exponent is continuous here: substitute the limit of the base
The limit of x4 is (-1)4 when x → -1
⇥1.1) Let's evaluate: (-1)4
⇥ⓘ An integer power is a repeated product. The minus signs cancel out in pairs, an even power of a negative number is positive: (-1)4 = (-1)·(-1)·(-1)·(-1) = 1
⇥ 1
ⓘ The limit of a product of finite limits is the product of the limits
The limit of 3x4 is 3 when x → -1
ⓘ The limit of a product of finite limits is the product of the limits
The limit of -6x is -6·(-1) when x → -1
⇥1.2) Let's evaluate: -6·(-1)
⇥ⓘ Two minus signs cancel out, the product of two negative numbers is positive: -6·(-1) = 6
⇥ 6
ⓘ The limit of a sum of finite limits is the sum of the limits
So the limit of 3x4 -6x + 1 is 3 + 6 + 1 when x → -1
⇥1.3) Let's calculate: 3 + 6 + 1
⇥ⓘ Start from 3 and move forward 6 on the number line: 3 + 6 = 9
⇥ 9 + 1
ⓘ Start from 9 and move forward 1 on the number line: 9 + 1 = 10
▶Limit:   10