limit as x approaches -1 of arccos(x)
Compute the limit of arccos(x) as x → -1
ⓘ The function arccos is continuous, its limit is its value at the limit of its argument
So the limit of arccos(x) is arccos(-1) when x → -1
⇥Let's evaluate: arccos(-1)
ⓘ acos, asin and atan give the angle whose cosine, sine or tangent is the number, here a remarkable value: arccos(-1) = π
▶Limit:   π
The numeric value of: π equals:
▷ ≈ 3.1416