limit as x approaches -6+ of sqrt(x+6)

Let's evaluate the limit of

\sqrt{x + 6}

when

x \to -6

⁺

ⓘ The limit of a sum of finite limits is the sum of the limits

The limit of

x + 6

is (

- 6 + 6

)⁺ when

x \to -6

⁺

⇥Let's calculate:

- 6 + 6

⇥ⓘ Start from

-6

and move forward

6

on the number line, up to zero:

- 6 + 6

0

⇥

0

ⓘ The function sqrt is continuous, its limit is its value at the limit of its argument

So the limit of

\sqrt{x + 6}

\sqrt{0}

⁺ when

x \to -6

⁺

⇥Let's evaluate:

\sqrt{0}

▶Limit:

0