limit x->0 tan(x)/x
1) Let's evaluate the limit of tan(x)x when x → 0
ⓘ The function tan is continuous, its limit is its value at the limit of its argument
The limit of tan(x) is tan(0) when x → 0
Let's evaluate: tan(0)
ⓘ The tangent is the y-coordinate (vertical axis) divided by the x-coordinate (horizontal axis) of the point reached on the unit circle after a rotation of 0 radians from the horizontal axis pointing to the right, provided the x-coordinate is not zero, this is a remarkable value: tan(0) = 0
0
For tan(x)x, we encounter the indeterminate form 0/0 as x tends to 0
2) We need a Taylor expansion for: tan(x)
Apply the Taylor development tan(A) + (1 + tan(A)2)·(X -A) of tan with X=x around A=0 (order N=1)
tan(0) + (1 + tan(0)2)·(x + 0)
ⓘ The tangent is the y-coordinate (vertical axis) divided by the x-coordinate (horizontal axis) of the point reached on the unit circle after a rotation of 0 radians from the horizontal axis pointing to the right, provided the x-coordinate is not zero, this is a remarkable value: tan(0) = 0■Adding 0 changes nothing: x + 0 = x
0 + (1 + 02)·x
3) We redo the calculation using the Taylor expansion: x
xx
ⓘ The original denominator must remain nonzero. The fraction is simplified by dividing the numerator and the denominator by their common factor x: xx = 1
1
So the limit of tan(x)x is 1 when x → 0
▶Limit:   1