limit x->1 (x^2-1)/(x-1)
1) Let's evaluate the limit of x2 -1x -1 when x → 1
ⓘ The power with a constant exponent is continuous here: substitute the limit of the base
The limit of x2 is 1 when x → 1
ⓘ The limit of a sum of finite limits is the sum of the limits
The limit of x2 -1 is 1 -1 when x → 1
⇥1.1) Let's calculate: 1 -1
⇥ⓘ Start from 1 and move back 1 on the number line, down to zero: 1 -1 = 0
⇥ 0
ⓘ The limit of a sum of finite limits is the sum of the limits
The limit of x -1 is 1 -1 when x → 1
⇥1.2) Let's calculate: 1 -1
⇥ⓘ Start from 1 and move back 1 on the number line, down to zero: 1 -1 = 0
⇥ 0
For x2 -1x -1, we encounter the indeterminate form 0/0 as x tends to 1
2) To find the limit, we factorize the numerator and the denominator:
x2 -1
For x2 -1, we recognize a difference of two squares: x2 -12. Apply a2 -b2 = (a -b)·(a + b), with a = x and b = 1
Factors found: (x + 1)·(x -1)
3) Let's reduce: (x + 1)·(x -1)x -1
ⓘ The original denominator must remain nonzero. The fraction is simplified by dividing the numerator and the denominator by their common factor x -1: (x + 1)·(x -1)x -1 = x + 1
x + 1
ⓘ The limit of a sum of finite limits is the sum of the limits
The limit of x + 1 is 1 + 1 when x → 1
Let's evaluate: 1 + 1
ⓘ Start from 1 and move forward 1 on the number line: 1 + 1 = 2
2
So the limit of x2 -1x -1 is 2 when x → 1
▶Limit:   2