limit x->infinity (exp(x)-1)/(exp(x)-x)
1) Let's evaluate the limit of exp(x) -1exp(x) -x when x+∞
The limit of exp(x) is +∞ when x+∞
The limit of exp(x) -1 is +∞ when x+∞
For exp(x) -x, the limit takes the indeterminate form +∞ + -∞ when x+∞
By comparative growth, exp(x) grows faster than x as x+∞:
The limit of exp(x) -x is +∞ when x+∞
For exp(x) -1exp(x) -x, the limit takes the indeterminate form +∞+∞ when x+∞
2) To find the limit, we divide the numerator and the denominator by exp(x):
Let's reduce: exp(x) -1exp(x)
1 -1exp(x)
3) Let's reduce: exp(x) -xexp(x)
1 -xexp(x)
We obtain a new fraction whose limit can be determined: 1 -1exp(x)1 -xexp(x)
The limit of -1exp(x) is 0⁻ when x+∞
The limit of 1 -1exp(x) is 1 when x+∞
For -xexp(x), the limit takes the indeterminate form +∞+∞ when x+∞
By comparative growth, exp(x) grows faster than x as x+∞:
The limit of -xexp(x) is 0⁻ when x+∞
The limit of 1 -xexp(x) is 1 when x+∞
The limit of 1 -1exp(x)1 -xexp(x) is 1 when x+∞
So the limit of exp(x) -1exp(x) -x is 1 when x+∞
Answer:   1