limit x->infinity x*ln(x)/exp(x)
Compute the limit of x·ln(x)exp(x) as x+∞
The limit of ln(x) is +∞ when x+∞
The limit of exp(x) is +∞ when x+∞
For ln(x)exp(x), we encounter the indeterminate form +∞+∞ as x tends to +∞
By comparative growth, exp(x) grows faster than ln(x) as x+∞:
The limit of ln(x)exp(x) is 0⁺ when x+∞
For x·ln(x)exp(x), the limit takes the indeterminate form +∞·0 when x+∞
To resolve the indeterminate form 0 × ∞, we rewrite the product x·ln(x)exp(x) as the quotient xexp(x)ln(x)
For exp(x)ln(x), the limit takes the indeterminate form +∞+∞ when x+∞
By comparative growth, exp(x) grows faster than ln(x) as x+∞:
The limit of exp(x)ln(x) is +∞ when x+∞
For xexp(x)ln(x), the limit takes the indeterminate form +∞+∞ when x+∞
By comparative growth, exp(x)ln(x) grows faster than x as x+∞:
The limit of xexp(x)ln(x) is 0⁺ when x+∞
So the limit of x·ln(x)exp(x) is 0⁺ when x+∞
Result:   0