limit x->+inf sqrt(x)/x
1) Compute the limit of xx as x → +∞
ⓘ This is a reference limit of the function sqrt
The limit of x is +∞ when x → +∞
For xx, we encounter the indeterminate form +∞+∞ as x tends to +∞
2) Let's apply L'Hôpital's rule (limit of a/b = limit of a'/b') by differentiating numerator and denominator:
3) Let's differentiate: ddx(x)
ⓘ The derivative of sqrt(x) is 1/(2*sqrt(x)): ddx(x) = 12x
12x
4) Let's differentiate: ddx(x)
ⓘ The derivative of x is 1: ddx(x) = 1
1
Using those derivatives, we obtain a new fraction whose limit can be computed:
ⓘ A quantity that grows without bound multiplied by a quantity not tending to 0 still grows without bound, the signs giving +∞ or -∞
The limit of 2x is +∞ when x → +∞
ⓘ A number divided by a quantity that grows without bound tends to 0
The limit of 12x is 0⁺ when x → +∞
So the limit of xx is 0⁺ when x → +∞
▶Limit:   0