line (1,3),(2,5)
The slope between the two points is y2 -y1x2 -x1: 5 -32 -1
⇥ⓘ The numerator and the denominator are computed before the division: 5 -3 = 2, 2 -1 = 1
⇥ 21
⇥ 2
The line passes through the first point with this slope: y = 2·(x -1) + 3
⇥ⓘ Expand by multiplying each term inside the parentheses: 2·(x -1) = 2x -2
⇥ y = 2x -2 + 3
ⓘ Start from -2 and move forward 3 on the number line, going past zero: -2 + 3 = 1
▶Line:   y = 2x + 1