m/6 =(m+1)/5
Let's solve in ℝ: m6 = m + 15
Let's sum the fractions: m6 -m + 15 = 0
ⓘ To add fractions, put them over the same denominator, then add the numerators: m6 -m + 15 = m·5 -(m + 1)·66·5
m·5 -(m + 1)·66·5 = 0
ⅰ 6·5 = 30
m·5 -(m + 1)·630 = 0
⇥Let's solve in ℝ: m·5 -(m + 1)·6 = 0
⇥ⓘ Expand by multiplying each term inside the parentheses: -(m + 1)·6 = -(m·6 + 6)
⇥ m·5 -(m·6 + 6) = 0
⇥ⓘ A minus sign before a parenthesis changes the sign of each of its terms: -(m·6 + 6) = -m·6 -6
⇥ m·5 -m·6 -6 = 0
⇥ⓘ Like terms are grouped by adding their coefficients: m·5 -m·6 = -m
⇥ -m -6 = 0
⇥ⓘ We add 6 to both sides
⇥ -m = 6
⇥ⓘ The sign of both sides is changed
▶Solution found: m = -6