-2(4y-7)+y>= 2y-(-5+y)
Let's solve in ℝ: -2·(4y -7) + y ≥ 2y -(-5 + y)
ⓘ A minus sign before a parenthesis changes the sign of each of its terms: -(-5 + y) = 5 -y
-2·(4y -7) + y ≥ 2y + 5 -y
ⓘ Like terms are grouped by adding their coefficients: 2y -y = y
-2·(4y -7) + y ≥ y + 5
ⓘ Expand by multiplying each term inside the parentheses: -2·(4y -7) = -(8y -14)
-(8y -14) + y ≥ y + 5
ⓘ A minus sign before a parenthesis changes the sign of each of its terms: -(8y -14) = -8y + 14
-8y + 14 + y ≥ y + 5
ⓘ Like terms are grouped by adding their coefficients: -8y + y = -7y
-7y + 14 ≥ y + 5
ⓘ We gather the terms in y on the right and the other terms on the left
14 -5 ≥ y + 7y
ⓘ Start from 14 and move back 5 on the number line: 14 -5 = 9■Like terms are grouped by adding their coefficients: y + 7y = 8y
9 ≥ 8y
ⓘ Both sides are divided by 8
▶Solution found: y ≤ 98
The numeric value of: y ≤ 98 is:
▷ y ≤ 1.125