-4(2-x)=4x-8
Let's solve in ℝ: -4·(2 -x) = 4x -8
-4·(2 -x) -4x + 8 = 0
ⓘ Expand by multiplying each term inside the parentheses: -4·(2 -x) = -(8 + 4·(-x))
-(8 + 4·(-x)) -4x + 8 = 0
ⓘ A minus sign before a parenthesis changes the sign of each of its terms: -(8 + 4·(-x)) = -8 -4·(-x)
-8 -4·(-x) -4x + 8 = 0
ⓘ Two minus signs cancel out: -4·(-x) = 4x■Start from -8 and move forward 8 on the number line, up to zero: -8 + 8 = 0
0 + 4x -4x = 0
ⓘ Adding 0 changes nothing: 0 + 4x = 4x■Like terms are grouped by adding their coefficients: 4x -4x = 0
0 = 0
▶Solution obtained: x ∈ ℝ