-4(v+4)=3(v+4)+7
Let's solve in ℝ: -4·(v + 4) = 3·(v + 4) + 7
ⓘ Expand by multiplying each term inside the parentheses: -4·(v + 4) = -(4v + 16), 3·(v + 4) = 3v + 12
-(4v + 16) = 3v + 12 + 7
ⓘ A minus sign before a parenthesis changes the sign of each of its terms: -(4v + 16) = -4v -16■Start from 12 and move forward 7 on the number line: 12 + 7 = 19
-4v -16 = 3v + 19
ⓘ We gather the terms in v on the right and the other terms on the left
-16 -19 = 3v + 4v
ⓘ Start from -16 and move back 19 more on the number line, away from zero: -16 -19 = -35■Like terms are grouped by adding their coefficients: 3v + 4v = 7v
-35 = 7v
ⓘ Both sides are divided by 7
v = -357
ⓘ We simplify the fraction by dividing the numerator and the denominator by 7, their greatest common divisor: -357 = -5
▶Solution obtained: v = -5