-4g^2-68g=172
1) Let's solve in ℝ: -4g2 -68g = 172
Since -4 ≠ 0, divide both sides by -4: g2 + 17g = -43
g2 + 17g + 43 = 0
Given the quadratic form ag2 + bg + c, you can calculate the discriminant: Δ = b2 -4ac. Here a = 1, b = 17 and c = 43
Δ = 172 -4·1·43
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: 172 = 17·17 = 289
Δ = 289 -4·43
ⓘ Multiplications are done before additions and subtractions: 4·43 = 4·(40 + 3) = 4·40 + 4·3 = 160 + 12 = 172
Δ = 289 -172
ⓘ Start from 289 and move back 172 on the number line: 289 -172 = 117
Δ = 117
As Δ > 0, the equation has two roots:
The quadratic formula gives g1 = -b -Δ2a = -17 -1172·1
g1 = -17 -1172
ⓘ We look for the largest square dividing 117, 9 = 32, and take it out of the root: 117 = 9·13 = 9·13 = 3·13■The minus sign is factored out, changing the sign of each term: -17 -3·13 = -(17 + 3·13)
g1 = -17 + 3·132
The quadratic formula gives g2 = -b + Δ2a = -17 + 1172·1
g2 = -17 + 1172
ⓘ We look for the largest square dividing 117, 9 = 32, and take it out of the root: 117 = 9·13 = 9·13 = 3·13
g2 = -17 + 3·132
▶Solutions obtained: g = { -17 + 3·132, 3·13 -172 }
2) The numeric value of: g = { -17 + 3·132, 3·13 -172 } is:
g = { ≈ -17 + 3·3.60562, ≈ 3·3.6056 -172 }
g = { ≈ -17 + 10.81672, ≈ 10.8167 -172 }
g = { ≈ -27.81672, ≈ -6.18332 }
▷ g = { ≈ -13.9083, ≈ -3.0917 }