-4x-23>= 2-3(3+2x)
Let's solve in ℝ: -4x -23 ≥ 2 -3·(3 + 2x)
ⓘ Expand by multiplying each term inside the parentheses: -3·(3 + 2x) = -(9 + 6x)
-4x -23 ≥ 2 -(9 + 6x)
ⓘ A minus sign before a parenthesis changes the sign of each of its terms: -(9 + 6x) = -9 -6x
-4x -23 ≥ 2 -9 -6x
ⓘ Start from 2 and move back 9 on the number line, going below zero: 2 -9 = -7
-4x -23 ≥ -7 -6x
ⓘ We add 23 to both sides■Start from -7 and move forward 23 on the number line, going past zero: -7 + 23 = 16
-4x ≥ 16 -6x
ⓘ We add 6x to both sides
-4x + 6x ≥ 16
ⓘ Like terms are grouped by adding their coefficients: -4x + 6x = 2x
2x ≥ 16
ⓘ Both sides are divided by 2
x ≥ 162
ⓘ We simplify the fraction by dividing the numerator and the denominator by 2, their greatest common divisor: 162 = 8
▶Solution found: x ≥ 8