-5(z+1)=-2z+10
Let's solve in ℝ: -5·(z + 1) = -2z + 10
ⓘ Expand by multiplying each term inside the parentheses: -5·(z + 1) = -(5z + 5)
-(5z + 5) = -2z + 10
ⓘ A minus sign before a parenthesis changes the sign of each of its terms: -(5z + 5) = -5z -5
-5z -5 = -2z + 10
ⓘ We gather the terms in z on the right and the other terms on the left
-5 -10 = -2z + 5z
ⓘ Start from -5 and move back 10 more on the number line, away from zero: -5 -10 = -15■Like terms are grouped by adding their coefficients: -2z + 5z = 3z
-15 = 3z
ⓘ Both sides are divided by 3
z = -153
ⓘ We simplify the fraction by dividing the numerator and the denominator by 3, their greatest common divisor: -153 = -5
▶Solution obtained: z = -5