-x^2+6x+3=0
1) Let's solve in ℝ: -x2 + 6x + 3 = 0
Since -1 ≠ 0, divide both sides by -1: x2 -6x -3 = 0
Given the quadratic form ax2 + bx + c, you can calculate the discriminant: Δ = b2 -4ac. Here a = 1, b = -6 and c = -3
Δ = (-6)2 -4·1·(-3)
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: (-6)2 = (-6)·(-6) = 36
Δ = 36 -4·(-3)
ⓘ Multiplications are done before additions and subtractions. Two minus signs cancel out, the product of two negative numbers is positive: -4·(-3) = 12
Δ = 36 + 12
ⓘ Start from 36 and move forward 12 on the number line: 36 + 12 = 48
Δ = 48
As Δ > 0, the equation has two roots:
The quadratic formula gives x1 = -b -Δ2a = -(-6) -482·1
x1 = 6 -482
ⓘ We look for the largest square dividing 48, 16 = 42, and take it out of the root: 48 = 16·3 = 16·3 = 4·3
x1 = 6 -4·32
ⓘ A fraction is simplified by dividing the numerator and the denominator by the same number: 6 -4·32 = 2·(3 -2·3)2 = 3 -2·3
x1 = 3 -2·3
The quadratic formula gives x2 = -b + Δ2a = -(-6) + 482·1
x2 = 6 + 482
ⓘ We look for the largest square dividing 48, 16 = 42, and take it out of the root: 48 = 16·3 = 16·3 = 4·3
x2 = 6 + 4·32
ⓘ A fraction is simplified by dividing the numerator and the denominator by the same number: 6 + 4·32 = 2·(3 + 2·3)2 = 3 + 2·3
x2 = 3 + 2·3
▶Solutions found: x = { 3 -2·3, 3 + 2·3 }
2) The numeric value of: x = { 3 -2·3, 3 + 2·3 } is:
x = { ≈ 3 -2·1.7321, ≈ 3 + 2·1.7321 }
x = { ≈ 3 -3.4641, ≈ 3 + 3.4641 }
▷ x = { ≈ -0.4641, ≈ 6.4641 }