(1+i)^2
Let's calculate: (1 + i)2
(1 + i)×(1 + i)
1×1 + 1×i + i×1 + i×i
1×1 = 11×i = ii×1 = ii×i = i2
1 + i + i + i2
i + i = 2ii2 = -1
1 + 2i -1
0 + 2i
Answer:   2i