(2x)/3 =3+x/2
Let's solve in ℝ: 2x3 = 3 + x2
Let's sum the fractions: 2x3 -3 -x2 = 0
ⓘ Like terms are grouped by adding their coefficients: 2x3 -x2 = x6
x6 -3 = 0
ⓘ To add fractions, put them over the same denominator, then add the numerators: x6 -3 = x -3·66
x -3·66 = 0
ⓘ Multiplications are done before additions and subtractions: 3·6 = 18
x -186 = 0
⇥Let's solve in ℝ: x -18 = 0
▶Solution found: x = 18