(3-x)/5 =2x-6
Let's solve in ℝ: 3 -x5 = 2x -6
Let's add fractions: 3 -x5 -2x + 6 = 0
ⅰ 3 -x5 -2x = (3 -x) + 5·(-2x)5
(3 -x) + 5·(-2x)5 + 6 = 0
ⓘ Multiplications are done before additions and subtractions. A single minus sign does not cancel out, the product of a negative number by a positive number is negative: 5·(-2) = -10■To add fractions, put them over the same denominator, then add the numerators: 3 -x -10x5 + 6 = (3 -x -10x) + 6·55
(3 -x -10x) + 6·55 = 0
ⓘ Like terms are grouped by adding their coefficients: -x -10x = -11x■Multiplications are done before additions and subtractions: 6·5 = 30
3 -11x + 305 = 0
ⓘ The numerator and the denominator are computed before the division: 3 + 30 = 33
33 -11x5 = 0
⇥Let's solve in ℝ: 33 -11x = 0
⇥ 11x = 33
⇥ⓘ Both sides are divided by 11
⇥ x = 3311
⇥We divide the numerator and denominator of 3311 by the common factor: 11, which gives the new expression: 3
▶Solution found: x = 3