(4x-3)/3 =(2x-1)/2
1) Let's solve in ℝ: 4x -33 = 2x -12
ⓘ A fraction whose numerator is a sum splits term by term, (a + b)/c = a/c + b/c: 2x -12 = x -12
4x -33 = x -12
2) Let's add fractions: 4x -33 -x + 12 = 0
ⅰ 4x -33 -x = (4x -3) + 3·(-x)3
(4x -3) + 3·(-x)3 + 12 = 0
ⓘ The minus sign is placed in front of the product: 3·(-x) = -3x■To add fractions, put them over the same denominator, then add the numerators: 4x -3 -3x3 + 12 = (4x -3 -3x)·2 + 33·2
(4x -3 -3x)·2 + 33·2 = 0
ⓘ Like terms are grouped by adding their coefficients: 4x -3x = x
ⅰ 3·2 = 6
(x -3)·2 + 36 = 0
Let's solve in ℝ: (x -3)·2 + 3 = 0
ⓘ Expand by multiplying each term inside the parentheses: (x -3)·2 = x·2 -6
x·2 -6 + 3 = 0
ⓘ Start from -6 and move forward 3 on the number line, getting closer to zero: -6 + 3 = -3
x·2 -3 = 0
x·2 = 3
ⓘ Both sides are divided by 2
▶Solution found: x = 32
3) The numeric value of: x = 32 equals:
▷ x = 1.5