(5x+3)^2=16 — step-by-step solution

Let's solve in

ℝ

{(5 x + 3)}^{2} = 16

ⓘ The two numbers whose square is

16

are

-4

and

4

5 x + 3 = -4

ⓘ We subtract

3

from both sides

5 x = -7

ⓘ Both sides are divided by

5

Solution found:

x = - \frac{7}{5}

5 x + 3 = 4

ⓘ We subtract

3

from both sides

5 x = 1

ⓘ Both sides are divided by

5

Solution obtained:

x = \frac{1}{5}

▶Solution:

x = {- \frac{7}{5}, \frac{1}{5}}

The numeric value of:

x = {- \frac{7}{5}, \frac{1}{5}}

is:

▷

x = {-1.4, 0.2}