(7-5x)/3 =2x-8
Let's solve in ℝ: 7 -5x3 = 2x -8
Let's sum the fractions: 7 -5x3 -2x + 8 = 0
ⅰ 7 -5x3 -2x = (7 -5x) + 3·(-2x)3
(7 -5x) + 3·(-2x)3 + 8 = 0
ⓘ Multiplications are done before additions and subtractions. A single minus sign does not cancel out, the product of a negative number by a positive number is negative: 3·(-2) = -6■To add fractions, put them over the same denominator, then add the numerators: 7 -5x -6x3 + 8 = (7 -5x -6x) + 8·33
(7 -5x -6x) + 8·33 = 0
ⓘ Like terms are grouped by adding their coefficients: -5x -6x = -11x■Multiplications are done before additions and subtractions: 8·3 = 24
7 -11x + 243 = 0
ⓘ The numerator and the denominator are computed before the division: 7 + 24 = 31
31 -11x3 = 0
⇥Let's solve in ℝ: 31 -11x = 0
⇥ 11x = 31
⇥ⓘ Both sides are divided by 11
▶Solution found: x = 3111
The numeric value of: x = 3111 is:
▷ x = ≈ 2.8182