(m+1)/m=5
1) Let's solve in ℝ: m + 1m = 5
We multiply both sides by m, nonzero for the fractions to be defined
m + 1m·m = 5m
ⓘ Multiplying a fraction by a term multiplies its numerator: m + 1m·m = (m + 1)·mm■The original denominator must remain nonzero. The fraction is simplified by dividing the numerator and the denominator by their common factor m: (m + 1)·mm = m + 1
m + 1 = 5m
ⓘ We gather the terms in m on the right and the other terms on the left
1 = 5m -m
ⓘ Like terms are grouped by adding their coefficients: 5m -m = 4m
1 = 4m
ⓘ Both sides are divided by 4
Candidates, pending the domain check: m = 14
For the expression m + 1m to exist, you must check: m ≠ 0
Domain constraints: m ≠ 0
▶Solution:   m = 14
2) The numeric value of: m = 14 equals:
▷ m = 0.25