(-8)^(-4/3) — step-by-step solution

Let's calculate:

{(-8)}^{- \frac{4}{3}}

ⓘ The factor is moved to the numerator or the denominator by changing the sign of its exponent, for a nonzero base:

{(-8)}^{- \frac{4}{3}}

\frac{1}{{(-8)}^{\frac{4}{3}}}

\frac{1}{{(-8)}^{\frac{4}{3}}}

ⓘ For a reduced rational exponent m/n with odd n, use the real root: the result is negative for odd m and positive for even m:

{(-8)}^{\frac{4}{3}}

8^{\frac{4}{3}}

\frac{1}{8^{\frac{4}{3}}}

ⓘ An exponent m/n means taking the nth root and then the mth power; here, the root of order

3

8

2

8^{\frac{4}{3}}

2^{4}

\frac{1}{2^{4}}

ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product:

2^{4}

2 \times 2 \times 2 \times 2

16

▶Result:

\frac{1}{16}

The numeric value of:

\frac{1}{16}

is:

▷

0.0625