(x-3)^2=10 — step-by-step solution

Let's solve in

ℝ

{(x - 3)}^{2} = 10

ⓘ The two numbers whose square is

10

are

- \sqrt{10}

and

\sqrt{10}

x - 3 = - \sqrt{10}

ⓘ We add

3

to both sides

x = - \sqrt{10} + 3

Solution found:

x = 3 - \sqrt{10}

x - 3 = \sqrt{10}

ⓘ We add

3

to both sides

x = \sqrt{10} + 3

Solution obtained:

x = 3 + \sqrt{10}

▶Solution:

x = {3 - \sqrt{10}, 3 + \sqrt{10}}

The numeric value of:

x = {3 - \sqrt{10}, 3 + \sqrt{10}}

equals:

x = {\approx 3 - 3.1623, \approx 3 + 3.1623}

▷

x = {\approx -0.1623, \approx 6.1623}