(z+3)^2=15 — step-by-step solution

Let's solve in

ℝ

{(z + 3)}^{2} = 15

ⓘ The two numbers whose square is

15

are

- \sqrt{15}

and

\sqrt{15}

z + 3 = - \sqrt{15}

ⓘ We subtract

3

from both sides

Solution obtained:

z = - \sqrt{15} - 3

z + 3 = \sqrt{15}

ⓘ We subtract

3

from both sides

Solution obtained:

z = \sqrt{15} - 3

▶Solution:

z = {- \sqrt{15} - 3, \sqrt{15} - 3}

The numeric value of:

z = {- \sqrt{15} - 3, \sqrt{15} - 3}

equals:

z = {\approx - 3.8730 - 3, \approx 3.8730 - 3}

▷

z = {\approx -6.8730, \approx 0.8730}