parity f(x)=x^2
Let's study the parity of x2 with respect to x
The domain is x ∈ ℝ
This domain is symmetric about 0: if x is in the domain, -x is too
Replace x by -x: f(-x) = (-x)2
⇥Let's calculate: (-x)2
⇥ⓘ With an even integer exponent, the minus sign in the base disappears; with an odd integer exponent, it moves in front of the power: (-x)2 = x2
⇥ x2
f(-x) = f(x): the function is even
▶Parity: even