parity f(x)=x^5
Let's study the parity of x5 with respect to x
The domain is x ∈ ℝ
This domain is symmetric about 0: if x is in the domain, -x is too
Replace x by -x: f(-x) = (-x)5
⇥Let's evaluate: (-x)5
⇥ⓘ With an even integer exponent, the minus sign in the base disappears; with an odd integer exponent, it moves in front of the power: (-x)5 = -x5
⇥ -x5
f(-x) = -f(x): the function is odd
▶Parity: odd