We add the definition: y = -4·sin(6x + π2) Let's find the smallest positive period of -4·sin(6x + π2) For a·sin(bx + c) + d, the period is T = 2·πabs(b). The nonzero factor a and the shifts c and d do not change the period The period of sin(x) is 2π radians The coefficient of x in 6x + π2 is 6 T = 2π6 ▶Period: π3 The numeric value of: π3 is: ≈ 3.14163 ▷ ≈ 1.0472