|2-x^3|<= 6
1) Let's solve in ℝ: |2 -x3| ≤ 6
|A| ≤ B is equivalent to -B ≤ A ≤ B
2) Let's solve in ℝ: 2 -x3 ≤ 6
ⓘ We gather the terms in x3 on the right and the other terms on the left
2 -6 ≤ x3
ⓘ Start from 2 and move back 6 on the number line, going below zero: 2 -6 = -4
-4 ≤ x3
The function x ↦ x3 being strictly increasing on ℝ, x3 ≥ -4 is equivalent to x ≥ -43 = -43
Solution obtained: x ≥ -43
3) Let's solve in ℝ: 2 -x3 ≥ -6
ⓘ We gather the terms in x3 on the right and the other terms on the left
2 + 6 ≥ x3
ⓘ Start from 2 and move forward 6 on the number line: 2 + 6 = 8
8 ≥ x3
The function x ↦ x3 being strictly increasing on ℝ, x3 ≤ 8 is equivalent to x ≤ 83 = 2
Solution found: x ≤ 2
Intersecting x ≤ 2 and x ≥ -43 gives x ∈ [-43, 2]
▶Solution:   x ∈ [-43, 2]
4) The numeric value of: x ∈ [-43, 2] equals:
▷ x ∈ [≈ -1.5874, 2]