shift y=3cos(x-1)-3 — step-by-step solution

Let's find the phase shift of

3 \cdot \cos (x - 1) - 3

For

a \cdot \cos (b x + c) + d

, write

b x + c = b \cdot (x + \frac{c}{b})

: the graph of

a \cdot \cos (b x) + d

is shifted horizontally by

- \frac{c}{b}

Here the angle is

x - 1

: b =

1

and c =

-1

, so the phase shift is -c/b =

1

1

> 0: the graph is shifted

1

to the right

▶Phase shift:

1