Let's reduce: log(3, 9x) -log(3, 3) ℹlog(3, 9x) = ln(9x)ln(3)‖-log(3, 3) = -ln(3)ln(3) ln(9x)ln(3) -ln(3)ln(3) ln(9x) -ln(3)ln(3) ℹln(9x) -ln(3) = ln(9x3) ln(9x3)ln(3) ▷Answer: ln(3x)ln(3)