Let's simplify: $\log (3,9x)-\log (3,3)$

ⓘ For strictly positive arguments, a sum of logarithms with the same base is the logarithm of the product, a difference that of the quotient: $\log (3,9x)-\log (3,3)$ = $\log (3,\frac{9x}{3})$

$\log (3,\frac{9x}{3})$

ⓘ A fraction is simplified by dividing the numerator and the denominator by the same nonzero number: $\frac{9x}{3}$ = $3x$

▶Simplified form:   $\log (3,3x)$