Let's simplify: $-\frac{0.8\times 5}{{(0.01\times 5^2+1)}^2}$

ⓘ Multiply without the decimal points, then put the point back by counting the decimals of both factors: $0.8\times 5$ = $\frac{8\times 5}{10}$ = $\frac{40}{10}$ = $4$■Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: $5^2$ = $5\times 5$ = $25$

$-\frac{4}{{(0.01\times 25+1)}^2}$

ⓘ Multiplications are done before additions and subtractions. Multiply without the decimal points, then put the point back by counting the decimals of both factors: $0.01\times 25$ = $\frac{25}{100}$ = $0.25$

$-\frac{4}{{(0.25+1)}^2}$

ⓘ Parentheses are computed first: $0.25+1$ = $1.25$

$-\frac{4}{{1.25}^2}$

ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: ${1.25}^2$ = $1.25\times 1.25$ = $1.5625$

$-\frac{4}{1.5625}$

▶Simplified form:   $-2.56$