simplify (4+5i)/(4+6i)
1) Let's simplify: 4 + 5i4 + 6i
ⓘ To make the denominator real, multiply the numerator and denominator by its conjugate, since (a+bi)(a-bi) = a²+b²: 4 + 5i4 + 6i = (4 + 5i)×(4 -6i)42 + 62
(4 + 5i)×(4 -6i)42 + 62
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: 42 = 4×4 = 16, 62 = 6×6 = 36
(4 + 5i)×(4 -6i)16 + 36
ⓘ The numerator and the denominator are computed before the division: 16 + 36 = 52
(4 + 5i)×(4 -6i)52
ⓘ A fraction is simplified by dividing the numerator and the denominator by the same number: (4 + 5i)×(4 -6i)52 = (4 + 5i)×(2 -3i)26
(4 + 5i)×(2 -3i)26
ⓘ Expand by multiplying each term inside the parentheses: (4 + 5i)×(2 -3i) = 4×2 + 4×(-3)i + 5i×2 + 5×i×(-3)×i
4×2 + 4×(-3)i + 5i×2 + 5×i×(-3)×i26
ⓘ Multiplications are done before additions and subtractions: 4×2 = 8, 5×2 = 10■Multiplications are done before additions and subtractions. A single minus sign does not cancel out, the product of a negative number by a positive number is negative: 4×(-3) = -12, 5×(-3) = -15■Multiplying powers with the same base adds the exponents: i×i = i2
8 -12i + 10i -15i226
ⓘ Like terms are grouped by adding their coefficients: -12i + 10i = -2i■Multiplying by -1 gives the opposite: -15×(-1) = 15■i^2 = -1, so the powers of i reduce to 1, i, -1 or -i: i2 = -1
8 -2i + 1526
ⓘ The numerator and the denominator are computed before the division: 8 + 15 = 23
23 -2i26
ⓘ A complex number is written in algebraic form a + b*i, a being its real part and b its imaginary part: 23 -2i26 = 2326 -113×i
▶Simplified form:   2326 -113×i
2) The numeric value of: 2326 -113×i equals:
▷ ≈ 0.8846 -≈ 7.6923×10-2×i