simplify (6-3i)/(4+2i)
1) Let's simplify: 6 -3i4 + 2i
ⓘ To make the denominator real, multiply the numerator and denominator by its conjugate, since (a+bi)(a-bi) = a²+b²: 6 -3i4 + 2i = (6 -3i)×(4 -2i)42 + 22
(6 -3i)×(4 -2i)42 + 22
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: 42 = 4×4 = 16, 22 = 2×2 = 4
(6 -3i)×(4 -2i)16 + 4
ⓘ The numerator and the denominator are computed before the division: 16 + 4 = 20
(6 -3i)×(4 -2i)20
ⓘ A fraction is simplified by dividing the numerator and the denominator by the same number: (6 -3i)×(4 -2i)20 = (6 -3i)×(2 -i)10
(6 -3i)×(2 -i)10
ⓘ Expand by multiplying each term inside the parentheses: (6 -3i)×(2 -i) = 6×2 + 6×(-i) -3i×2 -3×i×(-i)
6×2 + 6×(-i) -3i×2 -3×i×(-i)10
ⓘ Multiplications are done before additions and subtractions: 6×2 = 12, 3×2 = 6■The minus sign is placed in front of the product: 6×(-i) = -6i■Two minus signs cancel out: -3×(-i) = 3i
12 -6i -6i + 3×i×i10
ⓘ Like terms are grouped by adding their coefficients: -6i -6i = -12i■Multiplying powers with the same base adds the exponents: i×i = i2
12 -12i + 3i210
ⓘ i^2 = -1, so the powers of i reduce to 1, i, -1 or -i: i2 = -1■Multiplying by -1 gives the opposite: 3×(-1) = -3
12 -12i -310
ⓘ The numerator and the denominator are computed before the division: 12 -3 = 9
9 -12i10
ⓘ A complex number is written in algebraic form a + b*i, a being its real part and b its imaginary part: 9 -12i10 = 910 -65×i
▶Simplified form:   910 -65×i
2) The numeric value of: 910 -65×i equals:
▷ 0.9 -1.2i