Let's simplify: a3 + b3b2 -a2 We use a^3 + b^3 = (a + b)*(a^2 - a*b + b^2): a3 + b3 = (a + b)·(a2 -ab + b2) The original denominator must remain nonzero: a + b ≠ 0 and b -a ≠ 0 We also factor the difference of squares in the denominator: (a + b)·(a2 -ab + b2)(a + b)·(b -a) ▶Simplified form: a2 -ab + b2b -a